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Part 03 · Random variables and discrete distributions · Card 7 of 8

Geometric distribution

The geometric distribution models the number of trials until the first success, when each trial has success chance p. P(X = k) = (1-p)^(k-1) x p. The mean is 1/p.

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Analogy

Rolling a die until your first six: how many rolls do you wait?

Example

First six

p = 1/6P(first six on roll 3)= (5/6) x (5/6) x (1/6) = 25/216 = 0.116Mean wait = 1 / (1/6) = 6 rolls

In practice

Used for the number of attempts until a first sale, first defect or first pass.

Practice

Flashcards

  • Mean number of trials until first success?1/p, from the geometric distribution.

Questions people ask

Why is the mean of a geometric distribution 1 divided by p?

A rare success takes longer to arrive. If p is one in six, you wait about six trials on average, since each trial gives one-sixth of a success. The result 1/p matches this intuition and can be proved by summing the series.

Does the geometric distribution have a memory?

No. If you have failed ten times already, the chance of success on the next trial is still p. The remaining wait has the same distribution as when you started. This memoryless property is why past failures do not make success due.