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Chemistry (university) · Part 08

Acids, bases and electrochemistry

pH, weak acids, buffers, titrations, galvanic cells, cell potentials and electrolysis.

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  1. Brønsted-Lowry acids and basesA Brønsted-Lowry acid gives away a proton (H⁺). A base accepts one. When an acid loses a proton, it becomes its conjugate base. When a base gains one, it becomes its conjugate acid.
  2. pH and KwpH = −log[H⁺]. Water ionizes slightly: Kw = [H⁺][OH⁻] = 1.0×10⁻¹⁴ at 25 °C. So pH + pOH = 14. Each pH step is a factor of 10 in [H⁺].
  3. Weak acids and KaA weak acid only partly ionizes: HA ⇌ H⁺ + A⁻, with Ka = [H⁺][A⁻]/[HA]. A smaller Ka means a weaker acid. Use an ICE table, and often x is small enough to ignore beside the starting concentration.
  4. Buffer solutionA buffer resists pH changes. It holds a weak acid and its conjugate base together. Added acid is used up by the base, and added base is used up by the acid. Henderson-Hasselbalch: pH = pKa + log([A⁻]/[HA]).
  5. Acid-base titrationIn a titration, a solution of known concentration (the titrant) is added slowly to a measured sample until the reaction is just complete. This point is the equivalence point. An indicator or pH meter shows when it is reached.
  6. Galvanic cellA galvanic (voltaic) cell turns a spontaneous redox reaction into electric current. Oxidation happens at the anode and reduction at the cathode. Electrons flow through the wire from anode to cathode. A salt bridge keeps the charge balanced.
  7. Standard cell potentialThe standard cell potential is E°cell = E°cathode − E°anode, using standard reduction potentials in volts. A positive E°cell means the reaction is spontaneous. ΔG° = −nFE°, where F = 96,485 C/mol.
  8. Nernst equationThe Nernst equation gives the cell potential when concentrations are not standard: E = E° − (RT/nF) ln Q. At 25 °C, E = E° − (0.0592/n) log Q. As the cell runs, Q grows, E falls, and at equilibrium E = 0.
  9. ElectrolysisElectrolysis uses electricity to force a non-spontaneous reaction. Charge Q = current × time, and moles of electrons = Q / 96,485 C/mol. The moles of product follow from the electron count in the half-reaction.