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Part 10 · Organic reactions and mechanisms · Card 3 of 10

SN1 reaction

SN1 is substitution, nucleophilic, unimolecular. The leaving group first departs on its own, forming a carbocation. The nucleophile then attacks. Rate = k[substrate] only. Tertiary substrates react fastest, in polar solvents, and the product is mostly racemic.

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Analogy

A two-act play: first the actor leaves the stage (slow), then someone new walks on (fast).

Example

(CH₃)₃C–Br in water

Step 1 (slow): loses Br⁻, forms (CH₃)₃C⁺Step 2 (fast): water attacks cationRate depends only on [(CH₃)₃CBr]Product: (CH₃)₃C–OH

In practice

Tertiary alcohols turn into tertiary alkyl chlorides in concentrated HCl through an SN1 path.

Practice

Flashcards

  • What is the rate law for SN1?Rate = k[substrate]. The nucleophile does not appear.

Interview questions

  • Compare SN1 and SN2 in terms of rate law, substrate, stereochemistry and solvent.
    • SN2: second order, one step, inversion, primary substrates
    • SN1: first order, two steps, racemisation, tertiary substrates
    • SN2 favours strong nucleophiles, polar aprotic
    • SN1 favours polar protic solvents

Questions people ask

Why does SN1 give a racemic mixture?

The carbocation intermediate is flat. The nucleophile can attack from either face with equal chance, giving both mirror-image products in about equal amounts. In practice, a little more inversion product forms, because the leaving group briefly shields one face, so the mixture is not perfectly 50:50.

How do I choose between SN1 and SN2?

Look at the substrate first. Methyl and primary favour SN2, and tertiary favours SN1. Then look at the nucleophile and solvent: strong nucleophiles with polar aprotic solvents favour SN2, and weak nucleophiles in polar protic solvents favour SN1. Secondary halides can go either way.